For this article, let's pretend you have the following database table. There are two columns (I'm separating the fields with commas for readability), Item and Price:
Cheese Pizza, 1.00
Pepperoni Pizza, 1.50
Sausage Pizza, 1.50
Cheese Calzone, 1.50
Ham Calzone, 2.00
What if you want to populate a combo-box with your possible options? We can write php that generates a drop-down box that has five item choices in it, based on our table above. Here is the sample code:
<?php // Connect to the database mysql_connect("localhost", "user", "password") or die(mysql_error()); mysql_select_db("name") or die(mysql_error()); // Has the form been submitted? if (isset($_POST['item'])) { // The form has been submitted, query results $queryitem = "SELECT * FROM table WHERE item = '".$_POST['item']."';"; // Successful query? if($result = mysql_query($queryitem)) { // More than 0 results returned? if($success = mysql_num_rows($result) > 0) { // For each result returned, display it while ($row = mysql_fetch_array($result)) echo $row[serial]; } // Otherwise, no results, tell user else { echo "No results found."; } } // Error connecting? Tell user else { echo "Failed to connect to database."; } } // The form has NOT been submitted, so show the form instead of results else { // Create the form, post to the same file echo "<form method='post' action='example.php'>"; // Form a query to populate the combo-box $queryitem = "SELECT DISTINCT item FROM table;"; // Successful query? if($result = mysql_query($queryitem)) { // If there are results returned, prepare combo-box if($success = mysql_num_rows($result) > 0) { // Start combo-box echo "<select name='item'>n"; echo "<option>-- Select Item --</option>n"; // For each item in the results... while ($row = mysql_fetch_array($result)) // Add a new option to the combo-box echo "<option value='$row[item]'>$row[item]</option>n"; // End the combo-box echo "</select>n"; } // No results found in the database else { echo "No results found."; } } // Error in the database else { echo "Failed to connect to database."; } // Add a submit button to the form echo "<input type='submit' value='Submit' /></form>"; } ?>